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Q Linear equation system
Budget: $ 1.00
Posted On: Sep 24, 2012 at 9:43:25 pm
Closed On: Sep 24, 2012 at 12:00:00 am
Total Answers: 2
Status: Closed
Asked By chrom837
Rating:
Questions Asked:1
Questions Asked:1
2a+c+3d=0
2b-a-d-2d=2
a-b+d=2
2b-a-d-2d=2
a-b+d=2
Posted On: Sep 27, 2012 at 7:27:58 am
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Check out what I have attached, is the pathway to your success!
Posted On: Nov 30, 2012 at 8:54:45 am
Answered By MathTeacherTim
Rating:
Questions Answered:12
Questions Answered:12
My first assumption is that you meant to put 2a+b+3d=0 for the first equation, instead of a c. Otherwise, you could not find only one solution for the system.
Now, the first thing you want to do is list all the variables in the same order in each equation (and simplify the -d-2d in the second one), like this:
2a + b + 3d = 0
-a + 2b - 3d = 2
a - b + d = 2
